Trying using mysql_fetch_array, and using the field names. This is the recommended behaviour in PHP4:
$result = mysql_query($myQuery) //$myQuery gets defined earlier $resultCount = mysql_num_rows($result); $companyID = array(); while($query_data = mysql_fetch_array($result)) { $companyID[$query_data['CompanyID']] = $query_data['CompanyName']; $companyID_string .= "," . $query_data['CompanyID']; $companyName_string .= "," . $query_data['CompanyName']; } That probably isn't the problem, but hey.. you never know. I also noticed there's no ; after mysql_query ;) Lastly, you could also do (for debugging): while ($query_data = mysql_fetch_array($result)) { $tmp[] = $query_data; } echo '<pre>'; ob_start(); print_r($tmp); $text = ob_get_contents(); ob_end_clean(); echo htmlspecialchars($text); echo '</pre>'; To see what exactly is being returned. Mike Kurt Lieber wrote: >I'm executing a query that returns some a UID and a company name. I'm using >the following code to loop over that query result set: > > $result = mysql_query($myQuery) //$myQuery gets defined earlier > $resultCount = mysql_num_rows($result); > $companyID = array(); > while($query_data = mysql_fetch_row($result)) { > $companyID[$query_data[0]] = $query_data[1]; > $companyID_string .= "," . $query_data[0]; > $companyName_string .= "," . $query_data[1]; > } > >I've used $resultCount to verify the query is returning 4 rows. However, the >while loop above is looping over the results twice -- $companyID_string and >$companyName_string each have 8 values. Looking at the values shows that >it's the 4 rows duplicated. > >What the heck am I doing wrong? > >--kurt > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]