Trying using mysql_fetch_array, and using the field names. This is the 
recommended behaviour in PHP4:

        $result = mysql_query($myQuery) //$myQuery gets defined earlier
        $resultCount = mysql_num_rows($result);
        $companyID = array();
            while($query_data = mysql_fetch_array($result)) {
                $companyID[$query_data['CompanyID']] = $query_data['CompanyName'];
                $companyID_string .= "," . $query_data['CompanyID'];
                $companyName_string .= "," . $query_data['CompanyName'];
            }

That probably isn't the problem, but hey.. you never know.

I also noticed there's no ; after mysql_query ;)

Lastly, you could also do (for debugging):

while ($query_data = mysql_fetch_array($result)) {
    $tmp[] = $query_data;
}

echo '<pre>';
ob_start();
print_r($tmp);
$text = ob_get_contents();
ob_end_clean();
echo htmlspecialchars($text);
echo '</pre>';

To see what exactly is being returned.

Mike

Kurt Lieber wrote:

>I'm executing a query that returns some a UID and a company name.  I'm using 
>the following code to loop over that query result set:
>
>        $result = mysql_query($myQuery) //$myQuery gets defined earlier
>        $resultCount = mysql_num_rows($result);
>        $companyID = array();
>            while($query_data = mysql_fetch_row($result)) {
>                $companyID[$query_data[0]] = $query_data[1];
>                $companyID_string .= "," . $query_data[0];
>                $companyName_string .= "," . $query_data[1];
>            }
>
>I've used $resultCount to verify the query is returning 4 rows.  However, the 
>while loop above is looping over the results twice -- $companyID_string and 
>$companyName_string each have 8 values.  Looking at the values shows that 
>it's the 4 rows duplicated.
>
>What the heck am I doing wrong?
>
>--kurt
>



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