Or..
$required = array($name,$addr,$phone);
foreach($required as $x) {
if(!$x) {
print "error";
}
}
~Ryan
----- Original Message -----
From: "Philip Hallstrom" <[EMAIL PROTECTED]>
To: "Brandon Lamb" <[EMAIL PROTECTED]>
Cc: "PHP List" <[EMAIL PROTECTED]>
Sent: Tuesday, November 20, 2001 2:37 PM
Subject: [PHP] Re: Re: Re: How do I convert from perl to php?
> No, but this:
>
> $required = array('name','address','phone');
> foreach( $required as $key ) {
> if( empty($HTTP_POST_VARS[$key]) ) {
> print("Sorry, you left key empty.");
> }
> }
>
> should work.
>
>
> On Tue, 20 Nov 2001, Brandon Lamb wrote:
>
> > What about this?
> >
> > $required = array('name','address','phone');
> > while ( list($key, $value) = each ($required) ) {
> > if ( empty($value) ) {
> > print("Sorry, you left $key empty.");
> > }
> > }
> >
> > ----- Original Message -----
> > From: "Philip Hallstrom" <[EMAIL PROTECTED]>
> > Cc: <[EMAIL PROTECTED]>
> > Sent: Tuesday, November 20, 2001 2:22 PM
> > Subject: Re: Re: How do I convert from perl to php?
> >
> >
> > You could do something like this... there are lots of ways to validate
> > your data...
> >
> > while( list($key, $value) = each($HTTP_POST_VARS) ) {
> > if( empty($value) ) {
> > print("Sorry, you left $key empty.");
> > }
> > }
> >
> >
> >
> >
> > --
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> > For additional commands, e-mail: [EMAIL PROTECTED]
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> >
>
>
>
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