I was thinking that you could use a "pointer to var", eg:
$var = 'myarray["foo"]["bar"]["red"]["apple"]';
// this would obviously be created dynamically, hard coded for testing
$$var = $some_value1;
echo $myarray["foo"]["bar"]["red"]["apple"];
but when I tried it, it didn't work :(
looks like eval() to the rescue...
-----Original Message-----
From: Darren Gamble [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, December 04, 2001 10:37 AM
To: PHP List
Subject: [PHP] Multidimensional array construction
Here's a question for the list:
I have a two-dimensional array; essentially a list of arrays. Each element
(an array) can have any number of elements. As a small example:
(
( "foo" , "bar" , "red" , "apple" ),
( "foo" , "bar" , "red" , "car"),
( "foo" , "green" )
)
I would like to traverse this array and place all of the data into another
multidimensional array. The following statements illustrate how I'd like to
do this from the example:
$myarray["foo"]["bar"]["red"]["apple"] = $some_value1;
$myarray["foo"]["bar"]["red"]["car"] = $some_value2;
$myarray["foo"]["green"] = $some_value3;
Is there any way to easily do this in PHP? I could "cheat" and use eval(),
but there is probably a better way. I have thought of using each() or
references, but nothing has come to mind so far.
Any ideas? Should I just use eval() ?
============================
Darren Gamble
Planner, Regional Services
Shaw Cablesystems GP
630 - 3rd Avenue SW
Calgary, Alberta, Canada
T2P 4L4
(403) 781-4948
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