# Re: [PHP] counting with dates (help!)

```Well, I'll chime in as well. I'd recommend doing all your calculations
in timestamps in seconds, then convert the results into days, dates, or
whatever. If you only have a date to start with then convert to a
timestamp, do the calculation, and convert back. You could wrap it in a
function like this:```
```
<?php
function dateDiffInDays(\$date1,\$date2) {
\$date1Tm = strtotime(\$date1);
\$date2Tm = strtotime(\$date2);
\$diff = abs(\$date1Tm - \$date2Tm) / 86400;
return \$diff;
}

\$today = date("Ymd",mktime(0,0,0, date("m"), date("d"), date("Y")));
\$last_week = date("Ymd", mktime(0,0,0, date("m"), date("d")-7,
date("Y")));

print("today: \$today <br>\n");
print("last_week: \$last_week <br>\n");
print("diff in days: " . dateDiffInDays(\$last_week, \$today) . "<br>\n");
?>

On Thursday, February 7, 2002, at 04:21  PM, Sander Peters wrote:

> Hello,
>
>
> This is my problem:
>
> \$today = date("Ymd", mktime(0,0,0, date(m),date(d),date(Y)));
> \$last_week = date("Ymd", mktime(0,0,0, date(m),date(d)-7,date(Y)));
> echo (\$today - \$last_week);
> The result is a number like 8876 (20020107-20011231 = 8876)
> But in date thinking it should be 7!
>
> How can I let php count in real days/month/years in stead of numbers?
>
> Maybe this is a silly question, but anyone who has the answer would help
> me very much!
>
>
>
> --
> Met vriendelijke groet / With Greetings,
>
> Sander Peters
>
>    site: http://www.visionnet.nl/
>   email: mailto:[EMAIL PROTECTED]
> webmail: mailto:[EMAIL PROTECTED]
>
>
>
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```