Dani,
Not that I've tried this exact condition but the internal portion of this
array name works elsewhere. Give it a try.
$row['${"somename_".($var)}']
----- Original Message -----
From: Dani <[EMAIL PROTECTED]>
To: Stefan Rusterholz <[EMAIL PROTECTED]>;
<[EMAIL PROTECTED]>
Sent: Wednesday, January 16, 2002 7:33 AM
Subject: [PHP] CONTINUE - variable problem - help!
> hi again!
>
> I tried it but it desn't give me any result back.
> It dosn't print any error message but it desn't print my result either.
>
> this is how I place the code:
>
>
> echo "...some html code...";
> $row["somename_$var"];
> echo "...the continuation of the html code";
>
> thanks!
>
> Stefan Rusterholz wrote:
>
> > > Hi!
> > >
> > > I 'm trying not to hard code my php coding and I'm trying to pass a
> > > variable name into the $row[coloumname_$variable];
> > $row["columname_$variable"] should do it.
> > $row[constant] is threaten as constant which is normally not the
programmers
> > intention (set_error_reporting(0) and you'll see PHP's complaints about
it)
> > so PHP converts it to $row['constant'].
> > You may now understand, that PHP "translates" your code to
> > $row['coloumname_$variable'] whre $variable is a string and not a
variable.
> >
> > I hope, I could express myself understandable :)
> > best regards
> > Stefan Rusterholz
> >
> > --
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>
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