Well, add this and tell us what it says:
if(!$cursor) echo odbc_error($db).": ".odbc_errormsg($db);
right after that odbc_exec() call.
*always check for errors - and when you get one, show it!*
-Rasmus
On Sat, 2 Mar 2002, Dr. Shim wrote:
> I've tried, and tried. Reread, and reread. I can't at all find out what's
> wrong with these two lines of code.
>
> $SQLString = "INSERT INTO Movies (Title, Actors, Review, Reviewer, Short)
> VALUES ('$Title','$Actors','$Review','$Reviewer','$Short')";
> $cursor = odbc_exec($db, $SQLString);
>
> I have an if...then conditional statement causing echo to print out an error
> message if the $cursor returns false.
>
> The $cursor keeps returning false. I don't know why! My $db variable (which
> plugs into the odbc database) is fine. Those two lines have got to be the
> problem.
>
>
> Can you people help me out with this?
>
> If I have to give you my whole script (not very long) I will.
>
> Thanks for any help you can give me.
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
