Alex, If your link.php page has zero output to the screen, then you can do your database action and return to your main page by using a header command.
header("location: mypage.php"); On your link.php code, there should be no lines of code nor blank lines before the <?php call and no echo or print statements within the php code section. Hope this helps, Hugh p.s. you could also use a $php_self action in a form to get the same results. ----- Original Message ----- From: "Alex Vargas" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, March 04, 2002 12:03 AM Subject: [PHP] How to run a script leaving screen output of previous script > Hi. I want to run a php script without leaving the php that calls that > script. > > Let's say I have a script called mypage.php which displays html. There is a > link to link.php, which makes some database maintenance and has no output. I > want to be able to run link.php from mypage.php, but don't want to display > anything new on screen. > > As it is, when link.php runs, it displays a blank screen. I guess I could > insert a header to reload mypage.php, but I wonder if there is a way of not > leaving mypage.php at all. Is this posible? > > Thanks, > > -Alex > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php