I get the error: Fatal error: Only variables can be passed by reference in /home/tanguay/test/testxslt.php on line 7
when I run this code: <?php // Allocate a new XSLT processor $xh = xslt_create(); // Process the document, returning the result into the $result variable $result = xslt_process($xh, 'content.xml', 'website.xsl'); if ($result) { print "SUCCESS, sample.xml was transformed by sample.xsl into the \$result"; print " variable, the \$result variable has the following contents\n<br>\n"; print "<pre>\n"; print $result; print "</pre>\n"; } else { print "Sorry, sample.xml could not be transformed by sample.xsl into"; print " the \$result variable the reason is that " . xslt_error($xh) . print " and the error code is " . xslt_errno($xh); } xslt_free($xh); ?> Can anyone tell me why? Is this a problem with the parser or some other problem. I am new to the XSLT functions. Thanks, Edward -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php