On Thu, 2002-03-14 at 13:20, Phil Schwarzmann wrote:
> Why doesn't this work...
> I want to include a page in my code and send a variable to it but I get
> some funky error.
Please read this page carefully, especially the third paragraph and
Examples 11.3 and 11.5:
Hopefully that's help clear it up.
Essentially, you should be doing this:
$var = 'someval';
Hope this helps,
Torben Wilson <[EMAIL PROTECTED]>
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