> function somefunction($myvar) { > do something... > ... > ... $variablealacon = "\$myvar"; return $variablealacon; > } > > $varname = somefunction($myvar); > echo "$varname";
kodrik a écrit : > > function somefunction($myvar) { > > do something... > > ... > > ... > > return \$myvar; > > } > > > > $varname = somefunction($myvar); > > echo "$varname"; > > That won't work, because you escaped the $ sign, the variable won't get > processed and the name returned will be the one of the variable as it is > declared in the function, always the same. > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php