Try: $ary["this"] = array("that" => 1);
---
Scott Hurring
Systems Programmer
EAC Corporation
[EMAIL PROTECTED]
Voice: 201-462-2149
Fax: 201-288-1515
> -----Original Message-----
> From: Chris Boget [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, June 06, 2002 1:48 PM
> To: PHP General
> Subject: Re: [PHP] Arrays: Please help before I go insane?
>
>
> > Now, what I'm trying to do is build a tree based on the
> data in the DB.
> > It's working relatively ok if I uncomment the code that is
> on line 48 and
> > comment out line 49. However, what I really want to do is
> build a fully
> > associative array doing this and now** an array that has
> string keys but
> > then, those arrays having numeric keys (copy and run this code
> > un/commenting the lines above and you'll see what I mean).
>
> ** should be "not"
>
> To elaborate, what I'm trying to do is build an array that
> looks like this:
>
> $array["this"]["that"] = "whatever";
> $array["this"]["other"] = "whatever";
>
> and not one that looks like this:
>
> $array["this"][0] = "that";
> $array["this"][1] = "other";
>
> because I just want to be able to get the keys and not have to worry
> about when I should be using the value of the key or the value of the
> array element.
>
> Again, the problem that I'm having (as demonstrated by the code) is
> that when I'm trying to set it up so that it's like the first
> example above,
>
> $array["this"]
>
> isn't always evaluating as an array, though it always should.
>
> Chris
>
>
>
>
>
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