Hi Stuart,

Thanks. I added error_reporting (E_ALL); and it gave me the following error 
msg: "Warning: Undefined index: var in c:\program files\apache 
group\apache\htdocs\php\superstock\ssi\valuecalc\valuescreen\testsess.php on 
line 6"

Here is line 6: echo "session var: ".$_SESSION["var"]."<br>";

Apparently, there is no session variable! Does that mean the session was not 
created? I thought the session is created if I get the same session ID each 
time I reload the page.


P.S. I wish I could post the server address, but its on a private network. 
Only computers on the intra net have access to the server. I will see what I 
can do.

>From: Stuart Dallas <[EMAIL PROTECTED]>
>Reply-To: Stuart Dallas <[EMAIL PROTECTED]>
>Subject: Re[4]: [PHP] PLEASE HELP! session variable fails to persist!!
>Date: Sat, 15 Jun 2002 01:49:40 +0100
>On Saturday, June 15, 2002 at 1:42:45 AM, Zlutarch G. wrote:
> > I tried your script, but I couldn't get it to work. I guess it has to be
> > something wrong with my server configuration? I am using Apache 1.3.14. 
>I am
> > new to Apache, so I don't know what could possibly be the configuration
> > problem. Do you have any ideas? Thanks a lot.
>Do you get any errors? Add the following line immediately before the call 
>error_reporting (E_ALL);
>My guess is that it's failing to create the session, but if your error
>reporting is too low you may not be told about it.
>Is the server you are using public? Can you post the URL so we can take a
>PHP General Mailing List (http://www.php.net/)
>To unsubscribe, visit: http://www.php.net/unsub.php

Chat with friends online, try MSN Messenger: http://messenger.msn.com

PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to