Or just fopen() would work fine. -Kevin ----- Original Message ----- From: "Verdon Vaillancourt" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Tuesday, July 02, 2002 1:37 PM Subject: [PHP] Test if URL is alive before including a remote JS
> Hi :) > > Given I have some content embedded on my page by calling a remote JS and > occasionally the URL for the remote script is down causing my page to be > slow or fail, can I use the following example as a means to test and timeout > the remote server and skip the embedded JS, if the remote server isn't > responding properly? > > <?php > $fp = fsockopen ("www.theweathernetwork.com", 80, $errno, $errstr, 5); > if (!$fp) { > echo "sorry, not available"; > } else { > echo "<script language=\"JavaScript\" type=\"text/javascript\"> > <!-- var city = \"Muskoka_ON\"; //--> > </script> > <script language=\"javascript\" type=\"text/javascript\" > src=\"http://www.theweathernetwork.com/weatherbutton/test.js\"> > </script>"; > > } > ?> > > > TIA, verdon > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php