Thanks Kevin, Do I need to include 'fclose ($fp);' in there somewhere in this case?
On 7/2/02 3:41 PM, "Kevin Stone" <[EMAIL PROTECTED]> wrote: > Or just fopen() would work fine. > -Kevin > > ----- Original Message ----- >> Hi :) >> >> Given I have some content embedded on my page by calling a remote JS and >> occasionally the URL for the remote script is down causing my page to be >> slow or fail, can I use the following example as a means to test and > timeout >> the remote server and skip the embedded JS, if the remote server isn't >> responding properly? >> >> <?php >> $fp = fsockopen ("www.theweathernetwork.com", 80, $errno, $errstr, 5); >> if (!$fp) { >> echo "sorry, not available"; >> } else { >> echo "<script language=\"JavaScript\" type=\"text/javascript\"> >> <!-- var city = \"Muskoka_ON\"; //--> >> </script> >> <script language=\"javascript\" type=\"text/javascript\" >> src=\"http://www.theweathernetwork.com/weatherbutton/test.js\"> >> </script>"; >> >> } >> ?> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php