Thanks for pointing out the syntax error. I added the space after the -u but
it did not make any difference. It still gives the same result, that is
"Success", when it actually fails. What I am trying to figure out is how I
can tell if it failed (did not create the tables)? The $status variable does
not appear to hold the output of the system() function. Anyone know how to
get the output of system, passthru or exec into the $status variable to
check for success or failure?
"Analysis & Solutions" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> On Tue, Jul 09, 2002 at 06:09:36PM -0700, Fargo Lee wrote:
> > $status = system("mysql -umyuserid -pmypassword mydbname <
> You need a space between "-u" and "myuserid"
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