Thanks but it still returns "Success" on a failure. If anyone knows if it is
even possible to assign the output of system, passthru or exec to a variable
to check for success or failure and how to do it, please advise. The $status
variable seems to always be empty on success or failure when I try to echo

"Jason Wong" <[EMAIL PROTECTED]> wrote in message
> On Wednesday 10 July 2002 13:27, Fargo Lee wrote:
> > Thanks for pointing out the syntax error. I added the space after the -u
> > but it did not make any difference. It still gives the same result, that
> > "Success", when it actually fails. What I am trying to figure out is how
> > can tell if it failed (did not create the tables)? The $status variable
> > does not appear to hold the output of the system() function. Anyone know
> > how to get the output of system, passthru or exec into the $status
> > to check for success or failure?
> Your test for failure should be:
>   if ($status === FALSE)
> --
> Jason Wong -> Gremlins Associates ->
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
> /*
> Extreme fear can neither fight nor fly.
> -- William Shakespeare, "The Rape of Lucrece"
> */

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