thanks it worked ^^
-Nick
"Tom Rogers" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hi,
>
> Tuesday, July 23, 2002, 5:16:43 AM, you wrote:
>
> N> "Tom Rogers" <[EMAIL PROTECTED]> wrote in message
> N> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> >> Hello Nick,
> >>
> >> Monday, July 22, 2002, 8:47:39 PM, you wrote:
> >>
> >> N> i get php to allocate a colour then make it transparent using
> >> N> imagecolortransparent()
> >>
> >> N> instead of turning it transparent it becomes black.
> >>
> >> N> Is it something i'm doing wrong? can anyone help me?
> >>
> >> N> thanx in advance
> >>
> >> Post a bit of the code so we can see what you are doing
> >>
> >> --
> >> Tom
> >>
>
> N> $im = imagecreate($size, 21);
>
> N> $bgcolour =
> N>
imagecolorallocate($im,hexdec(substr($table[bg],0,2)),hexdec(substr($table[b
> N> g],2,2)),hexdec(substr($table[bg],4,2)));
> N> $fontcolour =
> N>
imagecolorallocate($im,hexdec(substr($table[fg],0,2)),hexdec(substr($table[f
> N> g],2,2)),hexdec(substr($table[fg],4,2)));
>
> N> if ($table[bg] == "no") {
> N>  $trans = imagecolortransparent ($im,$bgcolour);
> N> }
>
> probably what you need is:
>
> $im = imagecreate($size, 21);
> if ($table[bg] == "no") {
>    $bgcolour = imagecolorallocate($im,1,1,1);
>    $trans = imagecolortransparent ($im,$bgcolour);
> }
> else{
>      $bgcolour =
imagecolorallocate($im,hexdec(substr($table[bg],0,2)),hexdec(substr($table[b
g],2,2)),hexdec(substr($table[bg],4,2)));
> }
> $fontcolour =
imagecolorallocate($im,hexdec(substr($table[fg],0,2)),hexdec(substr($table[f
g],2,2)),hexdec(substr($table[fg],4,2)));
>
>
>
>
>
> --
> Best regards,
> Tom
>



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