On Friday 16 August 2002 22:12, lallous wrote: > Actually the interpreter will evaluate the '\1'. '1' . '\2' into one string > before passing it to preg_replace > So it will yield up as I originally wrote it, and it won't work.
Hmm, you're right. The interpreter is smarter than I thought :-/ -- Jason Wong -> Gremlins Associates -> www.gremlins.com.hk Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * /* "Why should we subsidize intellectual curiosity?" -Ronald Reagan */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php