On Thursday 05 December 2002 15:44, Ben C. wrote:
> I am now getting the following error:
> Warning: Supplied argument is not a valid MySQL-Link resource in
> on line 21
> Why do you think that is?
Try using mysql_error() after each of your mysql_*() functions.
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
Experience is not what happens to you; it is what you do with what happens
-- Aldous Huxley
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php