use header("Content-type: image/jpeg"); and then you can echo it's
content.
On Thu, 2003-02-20 at 17:30, Chad Day wrote:
> I'm trying to get weather channel information without using their form to
> submit the zip code .. the url format is :
>
> http://oap.weather.com/fcgi-bin/oap/generate_magnet?loc_id=$ZIP&code=689861&;
> destination=$ZIP
>
> so I tried:
>
> $weatherfile =
> readfile("http://oap.weather.com/fcgi-bin/oap/generate_magnet?loc_id=$_SESSI
> ON[ZIP]&code=689861&destination=$_SESSION[ZIP]");
> echo $weatherfile;
>
> but of course it just outputs the raw image data .. I tried echoing it out
> in a img src tag, same result. Is there some function I'm unaware of that
> will help me out here?
>
> Thanks,
> Chad
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