More specifically (since I just dealt with this issue myself), use fpassthru
(and be sure not to fclose the file pointer as it's automatically done by
fpassthru)
On 02/20/03 12:47 PM, "Mincu Alexandru" <[EMAIL PROTECTED]> wrote:
> use header("Content-type: image/jpeg"); and then you can echo it's
> content.
> On Thu, 2003-02-20 at 17:30, Chad Day wrote:
>> I'm trying to get weather channel information without using their form to
>> submit the zip code .. the url format is :
>>
>> http://oap.weather.com/fcgi-bin/oap/generate_magnet?loc_id=$ZIP&code=689861&;
>> destination=$ZIP
>>
>> so I tried:
>>
>> $weatherfile =
>> readfile("http://oap.weather.com/fcgi-bin/oap/generate_magnet?loc_id=$_SESSI
>> ON[ZIP]&code=689861&destination=$_SESSION[ZIP]");
>> echo $weatherfile;
>>
>> but of course it just outputs the raw image data .. I tried echoing it out
>> in a img src tag, same result. Is there some function I'm unaware of that
>> will help me out here?
>>
>> Thanks,
>> Chad
-m^2
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