i managed to complete it and it all works brilliantly.

thank you for putting me in the right direction

Mark Mckee wrote:
> hi all
> 
> I am definately stuck now. i have managed to insert data into my table 
> using php and sql staements.
> 
> I have also managed to display that data on a single page.
> 
> the points where i am stuck
> 
> 1) how do i display all the data contained in the table and not just the 
>   one row?
> 
> 2) i have my input form up and ready. a place for the header, test and a 
> drop down box containing the 40 pages i want to choose from to update. 
> how do i send the correct header text and the chioce in the drop down to 
>   the correct table?
> 
> i think thats it for now lol. any help would be grately appreciated
> 
> kind regards
> 
> Mark...
> 
> 
> 
> 
> Mark Mckee wrote:
> 
>>thank you for the help.
>>
>>i wil keep trying to get it working.
>>
>>Michael Sullivan wrote:
>>
>>
>>>On Tue, 2006-03-21 at 00:52 +0000, Mark Mckee wrote:
>>>
>>>
>>>
>>>>hi all
>>>>
>>>>i want to create an inut page for the content on my website. is it 
>>>>possible to have 1 data entry box and choose the specific what table
>>>>of 
>>>>a database to put it usign a drop down box?
>>>>
>>>>if so, can someone please point me in the right direction. i have
>>>>been 
>>>>troubling over this for the last few days
>>>>
>>>>thanks in adavce
>>>>
>>>>mark m...
>>>
>>>
>>>I don't see why this wouldn't be possible.  You would just use the table
>>>name selected from the list box in constructing the query string you use
>>>in your mysql_query.
>>>
>>>Ex.
>>>
>>>I select 'SomeTable' from a list box called 'list' and hit the Submit
>>>button.  Another page is called, in which is a line like this:
>>>
>>>$list = $_POST['list'];
>>>
>>>
>>>
>>>You code says:
>>>
>>>$query = "SELECT * FROM ".$list;
>>>
>>>Then you issue 
>>>
>>>$result = mysql_query($query, $link2DB) or die ("Could not access table
>>>$list:".mysql_error());
>>>
>>>or whatever you want... 
>>>
>>>
>>>
>>>
>>>
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>>
>>
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