> Is temporary-object behaviour supposed to happen > in cases like $obj->another->func(), or is this > an unintended side-effect of something else?
no side effect, happens each time you dereference more than one member. $obj->foo->bar->func(); will therefore create two temp objects. > > Does PHP usually create temp-objects when referencing > $obj->another, or is that behaviour only part of > the COM subsystem? it is the case for non-native php objects. the php com subsystem is only a wrapper that makes a com object behave like a regular php object. so if you do something like $foo->bar->func(); we first have to create a wrapper for 'bar' so that it behaves like a php object and we can call func() on it. doing $baz = $foo->bar; $baz->func(); does not change the fact that a wrapper for 'bar' is created, but in this case the wrapper is not temporary but it is assigned to '$baz'. due to a bug the temporary objects were not released but the named ones were released by phps garbage collector. this is fixed now !! > Sorry for asking questions that are probably obvious, > but i'm not really too familiar with the details > of PHP's object handling. noprob. regards, harald -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
