Hi, is the real name of your table test_tabel as in the code sample or test_table as in the text ?
Sven Schnitzke -----Ursprüngliche Nachricht----- Von: Rodrigo San Martin [SMTP:[EMAIL PROTECTED]] Gesendet am: Sonntag, 13. Oktober 2002 09:33 An: [EMAIL PROTECTED] Betreff: [PHP-WIN] PHP_SELF Hi Have a problem. Need to pass a multiple array through a form using a PHP_SELF. I pass it whith a hidden variabel but i get an error warning. "Warning: Supplied argument is not a valid MySQL result resource in..." The code is: $qu2 ="SELECT * FROM test_tabel ;"; $result = mysql_query($qu2); $num = mysql_num_rows($result); i take out some info from test_table (there are some questions in the table that the user need to answer), the user does some operation, clicks submit and is supposed to be presented whith the next question in the table. I pass the variable like this: <INPUT TYPE='hidden' VALUE='$result' NAME='result'> But no way josey. I get that warning. Anybody got i nice solution please. ------------------------------------------ Rodrigo San Martin Institutt for datateknologi og informatikk http://www.idi.ntnu.no/~rodrigo -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
