Sven,
Noticed the semi colon in your query string - I don`t think you should be
including that.  db says he uses it with no problems - but if you look up
mysql_query in the manual - it says  "The query string should not end with a
semicolon."

Either that, or maybe you lose the database connection (and result set) that
the $result variable originally pointed to when you recurse back into the
script - how big is the script? - too big to include in a mail?

CD


----- Original Message -----
From: "Sven Schnitzke" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, October 15, 2002 6:57 PM
Subject: WG: [PHP-WIN] PHP_SELF


> Hi,
> is the real name of your table test_tabel as in the
> code sample or test_table as in the text ?
>
> Sven Schnitzke
>
>
> -----Ursprüngliche Nachricht-----
> Von: Rodrigo San Martin [SMTP:[EMAIL PROTECTED]]
> Gesendet am: Sonntag, 13. Oktober 2002 09:33
> An: [EMAIL PROTECTED]
> Betreff: [PHP-WIN] PHP_SELF
>
> Hi
>
> Have a problem. Need to pass a multiple array through a form using a
> PHP_SELF.
> I pass it whith a hidden variabel but i get an error warning.
>
> "Warning: Supplied argument is not a valid MySQL result resource in..."
>
> The code is:
>
> $qu2             ="SELECT * FROM test_tabel ;";
> $result       = mysql_query($qu2);
> $num         = mysql_num_rows($result);
>
> i take out some info from test_table (there are some questions in the
table
> that the user need to answer), the user does some operation, clicks submit
> and is supposed to be presented whith the next question in the table. I
pass
> the variable like this:
>
> <INPUT TYPE='hidden' VALUE='$result' NAME='result'>
>
> But no way josey. I get that warning.
>
> Anybody got i nice solution please.
>
>
>
>
>
> ------------------------------------------
> Rodrigo San Martin
> Institutt for datateknologi og informatikk
>
> http://www.idi.ntnu.no/~rodrigo
>
>
>
>
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