and use a local solution but don't think that I can

On 11 February 2017 at 10:38, dean <deangwillia...@gmail.com> wrote:

> This works too but I really want to remove setq from the middle of doit
>
> : (de doit ()
>    (let L (0 0 0)
>       (setq L (insert '1 (remove '1 L) 2))
>       (prinl "L is " L)
>    )
> )
> -> doit
> : (doit)
> L is 200
> -> (2 0 0)
>
>
>
>
> On 11 February 2017 at 10:29, dean <deangwillia...@gmail.com> wrote:
>
>> Here's the desired behaviour using the above code
>>
>> : (setq L (0 0 0))
>> -> (0 0 0)
>> : (de doit ()
>>    #(let L (0 0 0)
>>       (setq L (insert '1 (remove '1 L) 2))
>>       (prinl "L is " L)
>>    #)
>> )
>> -> doit
>> : (doit)
>> L is 200
>> -> (2 0 0)
>>
>> I was after (2 0 0) using let L i.e. the two lines commented out which
>> would replace the top setq... line
>> but no go and probably quite rightly. It just that (let A 3......(inc
>> 'A)...allows A to have it's value altered but there doesn't seem to be a
>> way to bring inc/dec to bear on a list element in the same very influential
>> way.
>>
>> On 11 February 2017 at 10:23, dean <deangwillia...@gmail.com> wrote:
>>
>>> Hi Joh-tob & Joe
>>> With setq L.....(0 0 0) gets changed to (2 0 0) i.e. the replace is done
>>> by index not matching value
>>> With let L...(0 0 0) stays at (0 0 0)
>>> I'd wanted the former in conjunction with let.
>>> Thank you for the suggestion re need...and the explanation re let.
>>> I can do this with setq but was just wondering if there was a way around
>>> "setting" let'd values more than once...like you can with let'd
>>> atoms...using inc and dec.
>>> I don't think you can but didn't think you could with atoms until inc
>>> and dec came back as an answer on this forum...hence this question :).
>>> Thank you for your advice and best regards
>>> Dean
>>>
>>>
>>>
>>> On 11 February 2017 at 02:07, Joe Bogner <joebog...@gmail.com> wrote:
>>>
>>>> dean, is this what you are describing?
>>>>
>>>> (let L (list 1 2 3)
>>>>         (setq L (append L (4)))
>>>>         (printsp L) )
>>>>
>>>>
>>>> (1 2 3 4)
>>>>
>>>>
>>>> The key to this is understanding how let works. It restores the prior
>>>> value after execution. See http://software-lab.de/doc/refL.html#let
>>>>
>>>> Defines local variables. The value of the symbol sym - or the values of
>>>> the symbols sym in the list of the second form - ***are saved** and the
>>>> symbols are bound to the evaluated any arguments. The 64-bit version also
>>>> accepts lst arguments in the second form; they may consist only of symbols
>>>> and sublists, and match the any argument (destructuring bind). prg is
>>>> executed, then the symbols ***are restored to their original values***.
>>>>
>>>>
>>>>
>>>> On Fri, Feb 10, 2017 at 3:22 PM, dean <deangwillia...@gmail.com> wrote:
>>>>
>>>>> Hi
>>>>> I've seen that I can alter local/let'd atoms? via inc/dec i.e. (inc
>>>>> 'Some_atom)
>>>>> which gets me a long way...
>>>>> ...but what about list elements?
>>>>>
>>>>>
>>>>> (setq L (0 0 0))
>>>>> (de doit ()
>>>>>    #(let L (0 0 0)
>>>>>       (setq L (insert '1 (remove '1 L) 2))
>>>>>       (prinl "L is " L)
>>>>>    #)
>>>>> )
>>>>>
>>>>> When I "setq" L this works but can I do it (somehow) when L is created
>>>>> with "let"?
>>>>>
>>>>
>>>>
>>>
>>
>

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