The values from the command line will be stored in the *|@ARGV|* array.
Likely won't have any impact on the value of foo :(
JD
Vaughn Treude wrote:
Quick perl question:
I'm trying to run a perl script that is executable; that is, the file
has "x" permission and starts with this line:
#!/usr/bin/perl -w
There's a parameter in this script that's not defined by default, for
example
my $foo; # no default
If foo is not set, the script exits with an error. Normally I would
just modify the script but this script gets extracted from a shell
script that has the perl script and an rpm embedded in it. (How they
did that I don't know.) So I would expect there's a way to do this, but
there were no help files with the script.
The shell script invokes the install file like this:
./install_script *$
So I know that I can pass one or more arguments to the outer shell
script and they will get passed verbatim to the perl script.
Is there a to pass a value for foo into the script without modifying the
script?
Thanks in advance,
Vaughn
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JD Austin
Twin Geckos Technology Services LLC
email: [EMAIL PROTECTED]
http://www.twingeckos.com
phone/fax: 480.288.8195
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