On 7/6/07, Vaughn Treude <[EMAIL PROTECTED]> wrote:
Quick perl question: I'm trying to run a perl script that is executable; that is, the file has "x" permission and starts with this line: #!/usr/bin/perl -w There's a parameter in this script that's not defined by default, for example my $foo; # no default If foo is not set, the script exits with an error. Normally I would just modify the script but this script gets extracted from a shell script that has the perl script and an rpm embedded in it. (How they did that I don't know.) So I would expect there's a way to do this, but there were no help files with the script. The shell script invokes the install file like this: ./install_script *$ So I know that I can pass one or more arguments to the outer shell script and they will get passed verbatim to the perl script. Is there a to pass a value for foo into the script without modifying the script? Thanks in advance, Vaughn --------------------------------------------------- PLUG-discuss mailing list - [email protected] To subscribe, unsubscribe, or to change your mail settings: http://lists.PLUG.phoenix.az.us/mailman/listinfo/plug-discuss
I do not know Perl, but maybe if you find a perl FAQ on the web, you can search for something about a "persistent variable" or s. like that... if that's what it is. Just a guess, from -- Mike Schwartz Glendale AZ [EMAIL PROTECTED] [EMAIL PROTECTED]
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