thad,
run this and check the output. the -x prints commands and arguments
for debugging purposes and get back to us what's the output.
ssh ${HOST} 'bash -x /var/report/erreport.sh'
or
ssh ${HOST} 'ksh -x /var/report/erreport.sh'
or
replace bash/ksh on whatever shell you are using.
--
regards,
Andre | http://www.varon.ca
On 2/1/07, thad <[EMAIL PROTECTED]> wrote:
I have this snippet in from my script that will call or execute using
ssh in trusted hosts another script. The erreport.sh has an initial
function that will delete the previous errorlog.out. However, the
next line which verify the timestamp of the output script, shows
result that the old file was not overwitten or no new output got
created. What would be the better way of doing this? This script
produced the desired ouput if executed on cli at its host.
ssh ${HOST} '/var/report/erreport.sh'
ssh ${HOST} 'ls -la /var/report/errlog.out `hostname`' >> $BASE_DIR/UP_${FILE}
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