Rom Flores wrote:
> 115 or 220 V is already RMS value. The peak value is 220 * 1.414
>
> so ... P = IV
Not quite... since we're talking AC here, the correct formula would be
P = VI * pf
where pf = power factor or equal to the cosine of the phase angle.
Plain VI would yield the magnitude of the apparent power in Volt-Amperes.
So, plain voltmeter and ammeter would not give you the real power component,
but would give you the factors for the magnitude of the apparent power.
You'll need an AC wattmeter to get the real power.
Of course, P = VI would only apply to an AC circuit if it only contains
purely resistive components, but in the real world, because of the effect of
the magnetic filed around the conductor, you have inductance and since you
have two or more conductors near each other you'll capacitance. :)
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