Depending on your definition of quick:
ls -lR | grep ^[d-] | perl -ane '$user{$F[2]}++; $group{$F[3]}++; END{
print " Users\n"; for $s (keys %user) {print "$s $user{$s}\n"} print "
Groups\n"; for $s (keys %group) { print "$s $group{$s}\n"}}'
On 2017-12-15 11:55, Galen Seitz wrote:
Hi,
Can anyone suggest a quick way to get a count of the number files owned
by each uid, or alternatively, print each unique uid that exists in the
filesystem? Bonus points for doing the same thing for gid's in the
same
pass.
thanks,
galen
--
Michael Rasmussen, Portland Oregon
Be Appropriate && Follow Your Curiosity
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