On 12/15/17 11:55, Galen Seitz wrote:
> Hi,
>
> Can anyone suggest a quick way to get a count of the number files owned
> by each uid, or alternatively, print each unique uid that exists in the
> filesystem? Bonus points for doing the same thing for gid's in the same
> pass.
Thanks for the other suggestion.
I finally used the correct search terms and found what I wanted. I'm
running this now, but it's taking a while.
find / -path /tmp -prune -o -path /sys -prune -o -path /proc -prune -o -printf
%u:%g\\n | awk '{usergroup[$0]++}; END {for(key in usergroup) printf "%-20s
%d\n",key,usergroup[key]}'
Next time I will probably add "-uid +499", as I'm not interested in
system accounts.
galen
--
Galen Seitz
gal...@seitzassoc.com
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