In that case &foo would be &foo[0] it's implied
On 9/22/06, Russel Caldwell <[EMAIL PROTECTED]> wrote:
Here's what's confusing me. If I create a integer array I will get the
following:
int foo[10] = {1, 2, 3};
cout << &foo; //gives me the address foo
cout << foo; //gives me the address of of foo[0]
If I create a character array:
char foo[] = "Hello";
cout << &foo; //gives me the address of foo
cout << foo; //gives me the string stored in foo
What will give me the address of foo[0]?
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