When I do cout << &foo[0], I get "Hello". Why is that?
On 9/22/06, Steve <[EMAIL PROTECTED]> wrote:
In that case &foo would be &foo[0] it's implied
On 9/22/06, Russel Caldwell <[EMAIL PROTECTED]> wrote:
> Here's what's confusing me. If I create a integer array I will get the
> following:
> int foo[10] = {1, 2, 3};
>
> cout << &foo; //gives me the address foo
> cout << foo; //gives me the address of of foo[0]
>
> If I create a character array:
> char foo[] = "Hello";
>
> cout << &foo; //gives me the address of foo
> cout << foo; //gives me the string stored in foo
> What will give me the address of foo[0]?
>
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