Hi,
I want to replace a text string placed within squared bracket with an
empty string. For example:
sString="Hello [World]"
should get to
sStringAfterReplace="Hello "
I tried this using the regex-plugin. But I failed with escaping the
square bracket. What I did (I concentrate on the square bracket escaping):
returnCode=regex.replaceg(sString,"\[","",output)
The return code was 8 which indicates a wrong pattern ("\[").
Any idea how to escape the square brackets correctly?
How can I solve my original problem: replace the substring within the
square brackets with an empty string (including replacing the square
brackets) ? In Perl the correct pattern is "\[.*\]" - but this fails
with the regex-dll, cause of problems escaping square brackets ...
TIA
Johannes
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