> > lol! Gil, I'm amused by the phrase "increasing at an increasing > rate..." Would there ever be a situation where it's "decreasing at an > increasing rate." ??? <g>
Actually, yes. :) Suppose the stock market is dropping 10 points a day for a month. Then on day 32 it drops 11 points, then on day 33 it drops 12 points, on day 34 it drops 13 points. It's dropping (decreasing) at an increasing rate. When something increases at the same rate, velocity is constant, acceleration is 0. When velocity increases, acceleration is > 0. When velocity decreases, acceleration is < 0. And when acceleration increases.... well, that may be more than we all want to discuss right now. :) Whil _______________________________________________ Post Messages to: [email protected] Subscription Maintenance: http://leafe.com/mailman/listinfo/profox OT-free version of this list: http://leafe.com/mailman/listinfo/profoxtech Searchable Archive: http://leafe.com/archives/search/profox This message: http://leafe.com/archives/byMID/profox/[EMAIL PROTECTED] ** All postings, unless explicitly stated otherwise, are the opinions of the author, and do not constitute legal or medical advice. This statement is added to the messages for those lawyers who are too stupid to see the obvious.
