Trudging back to my days in calculus I go to the dictionary......

   f=: 1 2 1&p. 
   g=: 1 3 3 1&p. 
   x=: 10%~i=: i.8
   ]c=: (f*g) t. i
1 5 10 10 5 1 0 0
   6.2 ":(c p. x),:(f*g) x
ran with error:
|domain error: scriptd
|   6.2    ":(c p.x),:(f*g)x
|[-4] c:\users\owner\j701-user\temp\53.ijs
   
Without formatting  6.2 ":  I march on:

(c p. x),:(f*g) x
1 1.61051 2.48832 3.71293 5.37824 7.59375 10.4858 14.1986
1 1.61051 2.48832 3.71293 5.37824 7.59375 10.4858 14.1986
   ff=: 13 :'1 2 1 p. y'
   ff
1 2 1 p. ]
   gg=:1 3 3 1 p. ]
   gg
1 3 3 1 p. ]
   ]X=:10%~I=:i.8
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7
   (f I)-:ff I
1
   (g I)-:gg I
1
   ]C=:(ff*gg)  t. I
ran with error:
|rank error: scriptd
|   ]C=:    (ff*gg)t.I
|[-13] c:\users\owner\j701-user\temp\53.ijs
   
So, what happened now?

Linda

-----Original Message-----
From: programming-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Brian Schott
Sent: Monday, October 29, 2012 10:51 AM
To: programm...@jsoftware.com
Subject: Re: [Jprogramming] Taylor series

Yes, it does make sense. My bad.

---
(B=)

On Oct 29, 2012, at 10:27 AM, Raul Miller <rauldmil...@gmail.com> wrote:

> Brian, a dictionary page for t.
> http://www.jsoftware.com/help/dictionary/dtdotu.htm says:
> 
>        x u t.y is the product of (x^y) and u t. y .
> 
> The complex verb in my previous email was built to satisfy this
definition.
> 
> Does this make sense?
> 
> -- 
> Raul
> 
> 
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