Good one! I tend to overlook sparse arrays as I seem to encounter nonce errors when trying to use them for real.

Mike

On 04/11/2012 7:03 PM, R.E. Boss wrote:
Your ($#: I.@,)  can be replaced:

    ((4$. $.) -: $#: I.@,)  4 5$ 0 1 0
1


R.E. Boss


-----Oorspronkelijk bericht-----
Van: programming-boun...@forums.jsoftware.com 
[mailto:programming-boun...@forums.jsoftware.com] Namens Mike Day
Verzonden: zondag 4 november 2012 18:53
Aan: programm...@jsoftware.com
Onderwerp: Re: [Jprogramming] Arc consistency in J

As far as I can understand the "revise" verb,  you don't need the
adjacency matrix a, although it does help to have a 2-column matrix of
index pairs.

I think Raul has overlooked your use of the right argument ys within
that verb,  though he's right about selecting with it. Here's a
derivation of arcs without explicit recourse to the adjacency matrix
(I've just noticed that Raul presents a similar idiom):

          arcs=. ys  (]#~ (e.~ {."1))   ($#: I.@,)  *|:A

I. returns a vector of indices to the ravelled boolean;  $ #: turns them
into a matrix of pairs of indices to an array of the shape of |:A.

(]#~ (e.~ {."1)) selects those arcs with an element of ys as the
from-node (or perhaps they're the to-nodes?)

This form renders the arcs array already sorted,  but note that if you
do need to sort the elements of an array,  it's sufficient to use the
idiom  /: ~    (rather than ({~ /:)   .     Presumably sorting "arcs" is
merely a matter of taste.

It's quite nice to be able to input several components of an argument by
(local) name with
     'A a C'=.x
     'ys D'=. y
rather than
      A=. > 0{x
      a=. > 1{x
      ys=. > 0{y
      D=.  > 1{y

As A is invariant in "ac",   you could of course preset the array of
indices for all arcs in A,  aix =: ($#: I.@,)  *|:A    and use aix as an
input to "revise" instead of   a  .

I used *|:A or (0<|:A) here and wonder why you need to double its lower
diagonal elements.

I also wonder whether your example will still work if there are binary
constraints involving variables (say z and t) indexed with 2 or 3.  And
what happens if there are more than one binary constraints on a pair of
variables?  eg,  X+Y=4 AND X>Y ?

I'd have been very pleased with myself if I'd come up with code as good
as this when I started J - would be pretty pleased if I managed it now!

Mike


On 04/11/2012 2:40 PM, Raul Miller wrote:
In
     A=. 0= ? (2$n)$2       NB. generate random matrix of [0,1]

The 0= is unnecessary, and probably reflects a habit based on the
false idea that boolean algebra is does not have an integer domain.
Boolean rings have (subset of) integer domains, and [even after
redefinition] boolean algebra is a boolean ring.

If you ever want to treat Heyting Algebras or Bayesian Probability you
might also want to consider what happens when you replace the $2 with
$0.

I think I would also be more comfortable with
     2 2 $ ''; 'y'; 'x'; A
for the displayed table, but that's a minor quibble.

An alternative definition for adj might be
     adj=: <@I.@:*

But somewhere around here, I get lost.  Your use pattern for arcsX is:

     (i.n) arcsX A

where A has the shape n,n

What is the domain of the left argument of arcsX?  I am guessing that
it's either i.n or a single element choosen from i.n but if that is
the case, I think I'd define arcsX to only work for the i.n case --
the name says "arcs" after all.  Also, if I wanted to extract the
values from the result of arcsX which correspond to a single value
from i. n, that's simple enough -- I can select on the first column of
the result.

In other words, perhaps something like this:

     arcs=: $ #: I.@,
     arcs *A

Also, I have not taken the time yet, to read "revise", so I will stop here.

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