If A is nonnegative

   (<@I.@:*)A
+-++---+-+
|2||0 3|2|
+-++---+-+

Otherwise

   (0<@I.@:<])A
+-++---+-+
|2||0 3|2|
+-++---+-+


R.E. Boss


> -----Oorspronkelijk bericht-----
> Van: programming-boun...@forums.jsoftware.com 
> [mailto:programming-boun...@forums.jsoftware.com] Namens Linda Alvord
> Verzonden: zondag 11 november 2012 11:17
> Aan: programm...@jsoftware.com
> Onderwerp: Re: [Jprogramming] Arc consistency in J
> 
> Mike, I think this will work as an alternative to  adj
> 
>     A
> 0 0 1 0
> 0 0 0 0
> 2 0 0 1
> 0 0 2 0
>    adj
> <@#&0 1 2 3@(0&<)
>    adj A
> --TT---T-┐
> │2││0 3│2│
> L-++---+--
>    h
> 0 1 2 3 <@#~ 0 < ]
>    h A
> --TT---T-┐
> │2││0 3│2│
> L-++---+--
> 
>  Can anyone remove the final  @  from  h  ?
> 
> Linda
> 
> 
> -----Original Message-----
> From: programming-boun...@forums.jsoftware.com
> [mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Raul Miller
> Sent: Saturday, November 10, 2012 12:44 PM
> To: programm...@jsoftware.com
> Subject: Re: [Jprogramming] Arc consistency in J
> 
> On Sat, Nov 10, 2012 at 12:16 PM, Michal D. <michal.dobrog...@gmail.com>
> wrote:
> > Here X is telling us to use the constraint c1 (presumably b/c C is not
> > shown) between the variables 1 and 3 (0 based).  Likewise, use the
> > transpose going the other direction (3,1).
> 
> Ouch, you are correct, I did not specify C.  On retesting, though, it looks
> like my results stay the same when I use:
> 
> arccon=:3 :0
>    'D c1 X'=: y
>    'n d'=: $D
>    adj =: ((<@#)&(i.n)) @ (0&<)
>    A =: adj X
>    C=: a: , c1 ; (|:c1)
>    ac =: > @ (1&{) @ (revise^:_) @ ((i.n)&;)
>    ac D
> )
> 
> For longer scripts like this, I really need to get into the habit of
> restarting J for every test.  So that probably means I should be using jhs.
> 
> > Given the structure of X, only variables 1 and 3 can possibly change.
> > So if they are all changing something is definitely wrong.
> 
> This line of thinking does not make sense to me.  I thought that the
> requirement was that a 1 in D exists only when there is a valid relationship
> along a relevant arc.  If a 1 in D can also exist in the absence of any
> relevant arc, I am back to needing a description of the algorithm.
> 
> > Unfortunately I've run out of time to read the rest of your response
> > but hopefully I can get through it soon.  I've also wanted to write a
> > simpler version of the algorithm where the right argument of ac is
> > only D and it runs through all the arcs in the problem instead of
> > trying to be smart about which ones could have changed.
> 
> Yes... I am currently suspicious of the "AC-3 algorithm".
> 
> In the case of symmetric consistency, I think that it's unnecessary
> complexity, because the system converges on the initial iteration.
> 
> In the case of asymmetric consistency, I think that the work involved in
> maintaining the data structures needed for correctness will almost always
> exceed the work saved.
> 
> But I could be wrong.  I am not sure yet if I understand the underlying
> algorithm!
> 
> --
> Raul
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