the original e3 is also defined in the original post.
The line ( e3=: 5 5 $ e3 ) in my post is just reshaping the original e3 as
a table rather than a list.




On Tue, Dec 4, 2012 at 10:11 PM, Linda Alvord <[email protected]>wrote:

> Ric,
>
>     e3=: 5 5$ e3
>    f=.1 2 3 5 8 13 21
>    (e3 e."1 f)} (5 5$<'. '),:<'@ '
> |stack error: e3
> |   (    e3 e."1 f)}(5 5$<'. '),:<'@ '
>    ;"1 (e3 e."1 f)} (5 5$<'. '),:<'@ '
>
> When does ;"1  apply if there is already a "stack error" without?
>
> Linda
>
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]] On Behalf Of Ric
> Sherlock
> Sent: Tuesday, December 04, 2012 3:46 AM
> To: Programming JForum
> Subject: Re: [Jprogramming] Getting more than one value back from "From" or
> alternative approach
>
> Linda, you'll find f explained and defined in the original post. It is the
> Fibonacci series.
>
>
>
> On Tue, Dec 4, 2012 at 9:32 PM, Linda Alvord <[email protected]
> >wrote:
>
> > Now for this thread.....
> >
> > Do you pull  f  out of some strange "hat" somewhere?
> >
> > Linda
> >
> > -----Original Message-----
> > From: [email protected]
> > [mailto:[email protected]] On Behalf Of Ric
> > Sherlock
> > Sent: Monday, December 03, 2012 10:17 PM
> > To: Programming JForum
> > Subject: Re: [Jprogramming] Getting more than one value back from
> > "From" or alternative approach
> >
> > Does this provide something similar to what you are wanting?
> >
> >    e3=: 5 5$ e3
> >    ;"1 (e3 e."1 f)} (5 5$<'. '),:<'@ '
> > . @ . . .
> > . @ @ . .
> > . @ . @ .
> > . @ . . .
> > . . . . @
> >
> >
> >
> > On Tue, Dec 4, 2012 at 3:21 PM, PackRat <[email protected]> wrote:
> >
> > > I have an application where I have a numeric evolute that I want to
> > > visualize.  Essentially, I have a list of values within the evolute
> > > that I want to display as a given literal character, while the
> > > remaining values would be a default "background" literal character.
> > >
> > > Everything works fine until I get to a point where I need to select
> > > values in such a way that I retrieve not only the "anchor"
> > > (selected) value from a list of ordered display characters but also
> > > one or more (depending on how the ordered list is constructed)
> > > succeeding separating characters.  "From" seems to be the kind of
> > > thing I'd like to do, but that returns only a single value for each
> > > element of the lefthand argument.  In other words, I know that you
> > > can do something
> > > like:
> > >
> > >         0 4 10 18 { array
> > >
> > > which will return FOUR elements from "array".  However, since in my
> > > case, each of the elements in "array" is followed (separated) by a
> > > space character, what I *want* returned are four PAIRS of characters
> > > (the element and its succeeding space): 0-1, 4-5, 10-11, and 18-19.
> > >
> > > Is there some way to make "From" be able to do this, or can someone
> > > suggest another approach?  I'm stuck at the moment.  Here's a sample
> > > evolute of size 5:
> > >
> > >    13 14 15 16 17
> > >    12  3  4  5 18
> > >    11  2  1  6 19
> > >    10  9  8  7 20
> > >    25 24 23 22 21
> > >
> > > For this example's sake, I decided to "mark" the Fibonacci series
> > > (contained in a list):
> > >
> > >    f=. 1 2 3 5 8 13 21
> > >
> > > After the earlier half of the program does its thing (correctly),
> > > the next lines would be (e3 has 25 values):
> > >
> > >    e3=. 12 13 14 15 16 11 2 3 4 17 10 1 0 5 18 9 8 7 6 19 24 23 22
> > > 21
> > > 20
> > >
> > >    sqdata=. 'X @ @ . @ . . @ . . . . @ . . . . . . . @ . . . . '
> > >
> > >    e4=. (2 * e3) { sqdata    NB. this is the problem area
> > >
> > >    e=. (2*5 , 5) $ e4
> > >
> > > The end result (e) should look like this:
> > >
> > >    @ . . . .
> > >    . @ . @ .
> > >    . @ X . .
> > >    . . @ . .
> > >    . . . . @
> > >
> > > The reason I need the spacing characters is because a square doesn't
> > > look square on a screen or printer since characters are rectangular
> > > in shape (not square).  Looking square is important for my application.
> > >
> > > Thanks in advance for any help solving this!
> > >
> > >
> > > Harvey
> > >
> > > --------------------------------------------------------------------
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