Sorry about any misunderstanding. The method involves injecting a current into one node with the rest of the grid tied to ground at infinity. So one ampere flows out at infinity. The resistance from the point of injection to infinity is infinity so the voltage at the injection point is infinity.
On Sun, Jan 27, 2013 at 5:09 PM, Raul Miller <[email protected]> wrote: > On Sun, Jan 27, 2013 at 4:53 PM, Keith Park <[email protected]> wrote: > > The method of finding the resistance between the two nodes of an infinite > > grid of resistances (Don&Kathy Kelly) is erroneous. The method fails > > because a one ampere current flowing into the grid produces an infinite > > voltage. > > What do you mean by this? > > Are you claiming that "if one amp were injected into the grid, the > resulting voltage would be infinite"? That can only happen if the > distance is infinite, and is really as much an objection to the > concept of "infinite" as anything else. For a finite separation > between the two significant nodes, the voltage must be finite. > > Or, are you instead saying that the proposed method yields infinite > voltages for a finite separation? If so, I must confess that I did > not observe it doing any such thing, and I'd like some explanation > about how you get that result. > > Or did you really mean something else? > > Thanks, > > -- > Raul > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
