Ok, that clarifies your point.  Except, in Kelly's method, it's not
tied to ground at infinity.

The problem is to determine the resistance between two nodes, A and B,
which are a finite distance apart.  The method injects 1 amp of
current at A and grounds B.

-- 
Raul

On Sun, Jan 27, 2013 at 6:27 PM, Keith Park <[email protected]> wrote:
> Sorry about any misunderstanding.  The method involves injecting a current
> into one node with the rest of the grid tied to ground at infinity. So one
> ampere flows out at infinity.  The resistance from the point of injection
> to infinity is infinity so the voltage at the injection point is infinity.
>
> On Sun, Jan 27, 2013 at 5:09 PM, Raul Miller <[email protected]> wrote:
>
>> On Sun, Jan 27, 2013 at 4:53 PM, Keith Park <[email protected]> wrote:
>> > The method of finding the resistance between the two nodes of an infinite
>> > grid of resistances (Don&Kathy Kelly) is erroneous. The method fails
>> > because a one ampere current flowing into the grid produces an infinite
>> > voltage.
>>
>> What do you mean by this?
>>
>> Are you claiming that "if one amp were injected into the grid, the
>> resulting voltage would be infinite"?  That can only happen if the
>> distance is infinite, and is really as much an objection to the
>> concept of "infinite" as anything else.  For a finite separation
>> between the two significant nodes, the voltage must be finite.
>>
>> Or, are you instead saying that the proposed method yields infinite
>> voltages for a finite separation?  If so, I must confess that I did
>> not observe it doing any such thing, and I'd like some explanation
>> about how you get that result.
>>
>> Or did you really mean something else?
>>
>> Thanks,
>>
>> --
>> Raul
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