OK, I think I've got it, thanks.  I was using  --  for a bidirectional 
connection.  --Kip

Sent from my iPad


On Feb 15, 2013, at 7:47 PM, Raul Miller <[email protected]> wrote:

> On Fri, Feb 15, 2013 at 7:23 PM, km <[email protected]> wrote:
>> My code is for directed graphs as defined in Graphs in Computer Science:
>> 
>> http://web.cecs.pdx.edu/~sheard/course/Cs163/Doc/Graphs.html
> 
> This is consistent with my intent when I used the phrase.
> 
>> However, suppose our undirected graph is
>> 
>> 0--1--2--3  (the only edges are those shown).
>> 
>> Am I right that every set of two nodes is visitable from node 2?  These are
> 
> 
> I cannot say for sure, because you have not indicated the direction of
> the connection.  If the connections are all bi-directional, then yes.
> But I would have diagramed that something like this:
> 
> 0<-->1<-->2<-->3
> 
>> {0 1} contained in 0--1--2
>> 
>> {0 2} contained in 0--1--2
>> 
>> {0 3} contained in 0--1--2--3
>> 
>> {1 2} contained in 1--2
>> 
>> {1 3} contained in 1--2--3
>> 
>> {2 3} contained in 2--3
>> 
>> ( No order is implied in the conventional set notation {a b} )
> 
> I am not sure what you are getting at, here, But I will note that the
> relevant visitable sets here (assuming 2-way connections) are:
> 
> 1 node:
> {2}
> 
> 2 nodes:
> {1 2}
> {2 3}
> 
> 3 nodes:
> {0 1 2}
> {1 2 3}
> 
> 4 nodes:
> {0 1 2 3}
> 
> On the other hand if, for example, the connections only went from left
> to right, the only visitable sets would be:
> 
> 1 node:
> {2}
> 
> 2 nodes:
> {2 3}
> 
> That said, yes - ordering is irrelevant when discussing sets. It's
> their construction - determining their contents - where ordering is
> relevant.
> 
>> Kip
>> 
>> P.S.  I do not expect my directed graph code to be efficient for large 
>> graphs and long chains, but I will experiment and report back.
> 
> Thanks!
> 
> -- 
> Raul
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