I apologize for being late on this thread.

The limit in question does not require the full fire-power of Wolfram
Alpha, adequate though that might be: I would expect a Calculus I student
to be able to figure it out.

The only non-obvious fact is (sin h)/h->1 as h->0, which you need so that
you can differentiate sin and cos using the definition.

With this in mind, and remembering sin x=cos ((pi/2)-x), etc.:

(x/4)tan (pi/2)(1-x)=(x/4)(sin (pi/2)(1-x))/(cos (pi/2)(1-x))

=(x/4)(cos (pi/2)x)/(sin (pi/2)x).

As x->0, the cosine term goes to 1, and x/(sin(pi/2) x)->1/(pi/2) using
the fact above.  This gives the result.

Best wishes,

John

Jose Mario Quintana wrote:
> I asked WolframAlpha the following: limit of ((x/4) tan((pi/2)(1-x))) as
> x-> 0 and it replied: 1/(2 Pi) (together with a nice graph).
>
>
> On Wed, Feb 27, 2013 at 10:41 AM, Raul Miller <rauldmil...@gmail.com>
> wrote:
>
>> On Wed, Feb 27, 2013 at 7:30 AM, Aai <agroeneveld...@gmail.com> wrote:
>> >>     (*:100)&* @: area _
>> >> 0
>> >> No, unfortunately J does not interpret the above sentence in that
>> sense.
>> >
>> > If I'm not wrong then J is right about this one:
>> >
>> >                pi(n-1)              pi 0
>> >             tg -------          tg ----
>> >                  2 n                 2          0
>> >    lim    --------------   =   ---------- =    ---- = 0
>> >  n -> oo       4 n                oo            oo
>> >
>> > But the accuracy gives us a much earlier decline to zero, because
>> ...
>>
>> It's usually a mistake to use infinity in calculations - infinity is
>> an inconsistent number so you should expect inconsistent results when
>> it is used in calculations.  (Something related often happens when
>> reasoning about division by an unknown sum.)
>>
>> Infinity is mostly convenient way of indicating neglect and, ideally,
>> focussing the conversation elsewhere.
>>
>> --
>> Raul
>> ----------------------------------------------------------------------
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>>
> ----------------------------------------------------------------------
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>


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