On Wed, Oct 30, 2013 at 2:51 AM, Don Kelly <[email protected]> wrote: > You are right but it is a bit of serendipity What I wanted is (a*b+ > b*c+c*a ) % c a b . > it doesn't matter how the pairs are formed in the numerator ac+ba+cb is > the same. >
Like this? F=: +/ .* (</~i.3) +/ .* ] % */ That's probably awful for speed, but it does express the idea. Thanks, -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
