I made an error (BIG GOOF)and gave a problem other than what I wanted so
I sent you and Raul on a wild goose chase.
Your
(+/@(*/)@(,: 1&|.) % */) 2 3 5
and Raul's
((+/ .* 1&|.) % */) 2 3 5
Agree and are more material to study, Thanks
Don
On 30/10/2013 5:59 AM, Jan-Pieter Jacobs wrote:
I'd write it tacitly like this:
(+/@(*/)@(,: 1&|.) % */) a b c
This is mainly motivated by the fact that a * b + b* c + c*a can be
expressed as multiplying with a shifted version, then summing.
Jan-Pieter
2013/10/30 Raul Miller <[email protected]>
On Wed, Oct 30, 2013 at 2:51 AM, Don Kelly <[email protected]> wrote:
You are right but it is a bit of serendipity What I wanted is (a*b+
b*c+c*a ) % c a b .
it doesn't matter how the pairs are formed in the numerator ac+ba+cb is
the same.
Like this?
F=: +/ .* (</~i.3) +/ .* ] % */
That's probably awful for speed, but it does express the idea.
Thanks,
--
Raul
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