ab+bc+ca is 1/2 the permanent. Cute.
Henry Rich
On 10/30/2013 11:20 PM, David Lambert wrote:
By chance is ab + bc + ab the permanent of
1j1#"1 '1',,:~'abc'
1 1 1
a b c
a b c
>From: Raul Miller <[email protected]>
>To: Programming forum <[email protected]>
>Subject: Re: [Jprogramming] making this tacit
>Message-ID:
> <cad2jou8jgv0x-9jejsuhtsrixryc2bkoj4gkvdwnsveznjr...@mail.gmail.com>
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>
>On Wed, Oct 30, 2013 at 2:51 AM, Don Kelly <[email protected]> wrote:
>
>> You are right but it is a bit of serendipity What I wanted is (a*b+
>> b*c+c*a ) % c a b .
>> it doesn't matter how the pairs are formed in the numerator ac+ba+cb is
>> the same.
>>
>
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