Also worth noting:
,.&.": 345
3 4 5
I stole this cute phrasing from Björn, but the basic premise is: convert the
integer to string representation (":), break it up into its component
characters, which correspond to its individual digits (,.), and then convert
those characters back into integers (&.).
Plenty of other ways to phrase it, some of which will permit higher-dimensional
input (,.&.":"0 works fine on any array, but verbs which process arrays in toto
typically have better performance than low-rank verbs which have to break up
large arguments first).
-Dan
> On May 9, 2014, at 2:40 AM, Roger Hui <[email protected]> wrote:
>
> 10&#.^:_1 ]314159
> 3 1 4 1 5 9
>
> Alternatively:
>
> ndigits=: 1 + [: <. [ ^. 1 >. ]
> 10 ndigits 314159
> 6
> (10 $~ 10 ndigits 314159)#: 314159
> 3 1 4 1 5 9
> digits=: ([ $~ ndigits) #: ]
> 10 digits 314159
> 3 1 4 1 5 9
>
> 16 digits 314159
> 4 12 11 2 15
>
>
>
>
>
>> On Thu, May 8, 2014 at 11:33 PM, Jon Hough <[email protected]> wrote:
>>
>> I want to get the (base 10) digits of an integer as an array.
>> e.g. 2343 becomes an array 2 3 4 3
>> My attempt is:
>>
>> tens =. 10 $ 10 tens #: 345
>> result: 0 0 0 0 0 0 0 3 4 5
>> I created the initial array tens as a 10 element array, and f course now I
>> have way too many leading zeros in my result.
>> How should I do this properly, returning no leading zeros, for an
>> arbitrary size integer?
>> Thanks.
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