This pushes the idea a little further.
Notice that dd was defined previously.
({:"1 dd) (<@}:"1 dd)}0 $. 1 $. 15 5
0 4 3 0 0
0 0 5 9 0
0 6 0 0 0
0 10 0 0 0
0 0 0 0 0
0 0 0 10 0
0 0 0 0 0
0 0 10 0 10
0 0 0 0 0
0 0 0 20 0
0 0 11 0 0
0 0 0 0 0
0 0 0 0 0
0 15 0 0 0
0 0 12 0 0
On Fri, Jun 27, 2014 at 12:24 PM, Brian Schott <[email protected]>
wrote:
> I don't quite have all the details worked out, but I am thinking in the
> following direction.
>
> data=: 0 : 0 NB. notice this is different from June's data
> 0 p1 4
> 2 p1 6
> 3 p1 10
> 13 p1 15
> 0 p2 3
> 1 p2 5
> 7 p2 10
> 10 p2 11
> 14 p2 12
> 1 p3 9
> 5 p3 10
> 9 p3 20
> 7 p4 10
> )
> $dd =. ".@(-.&'p') ;._2 data
>
>
> Now I want to use scarce arrays $. on dd, but cannot figure out how
> exactly. I thought I would study the following example from the Vocabulary
> page, but I don't remember how to rewrite dd as a sparse array.
>
> ] d=: (?. 3 4$2) * ?. 3 4$100
> 0 0 0 0
> 85 0 0 0
> 0 59 33 0
> ] s=: $. d
> 1 0 │ 85
> 2 1 │ 59
> 2 2 │ 33
>
> In other words I don't know how to manually create an artificial version
> of the noun s above. I know it can be done. And if that is done with my
> noun dd, then it should be simple to create your result.
>
>
> --
> (B=)
>
--
(B=)
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