This must be viewed with a nonproportional font.
It attempts to show that deb removes both leading and trailing spaces, but
deb1 now only removes trailing spaces.
(,:1j0&":@(10&|)@i.@#)deb ' abc de g hij k '
abc de g hij k
01234567890123
deb1 =: #~ ( 1 ,~ [: -. ' ' -:"1 (}: ,. }.) )
(,:1j0&":@(10&|)@i.@#)deb1 ' abc de g hij k '
abc de g hij k
0123456789012345
deb1 =: #~ ( (' ' ~: {:) ,~ [: -. ' ' -:"1 (}: ,. }.) )
(,:1j0&":@(10&|)@i.@#)deb1 ' abc de g hij k '
abc de g hij k
012345678901234
On Mon, Jul 14, 2014 at 10:29 AM, Kip Murray <[email protected]> wrote:
> Correction:
>
> deb1 =: #~ ( (' ' ~: {:) ,~ [: -. ' ' -:"1 (}: ,. }.) )
>
> (Now treats a trailing blank as an extra blank.)
>
> --
(B=)
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